1. a= 6 h= a (pierwiastek)3/2 h=3(pierwiastki z 3) r=2/3 h r= 2/3*3(pierwiastki z 3) r=2(pier. z 3) P=pi * r2 P=12pi
1. a = 6 r = 2/3h h = a√3/2 r = 2/3*a√3/2 = a√3/3 = 6√3/3 = 2√3 P = πr² P = π*(2√3)² = π*4*3 P = 12π 2. Ob = 22 Ob = 2a+2b = 22 2a+2b = 22 |:2 a+b = 11 d = √65 a²+b² = d² a²+b² = (√65)² a+b = 11 a²+b² = (√65)² a = 11-b (11-b)²+b² = (√65)² a = 11-b 121-22b+b²+b² = 65 a = 11-b 2b²-22b = 65-121 a = 11-b 2b²-22b = -56 |:2 a = 11-b b²-11b = -28 a = 11-b b²-11b+28 = 0 Δ = b²-4ac (a=1, b=-11, c = 28) Δ = (-11)²-4*1*28 Δ = 121-112 Δ = 9 Δ >0 czyli: x1 = (-b+√Δ)/2a (√Δ= √9=3) x1 = 11+3 /2*1 x1 = 14/2 = 7 x2 = (-b-√Δ)/2a x2 = 11-3)/2 x2 = 8/2 x2 = 4 b = 7 to a = 11-b = 11-7 = 4 b = 4 to a = 11-4 = 7 P = ab P = 4*7 = 28
