PILNE !!! W jakiej odleglosci od siebie musza sie znalezc dwa identyczne ladunki o wartosciach g=10 do potegi -6 C aby ich sila byla rowna F=4 x 10 do potegi 5 N

Ponieważ [latex]F=frac{kq_1q_2}{r^2}[/latex], to [latex]r=sqrt{frac{kq_1q_2}{F}}=sqrt{frac{9*10^{9}*10^{-6}*10^{-6}}{4*10^5}}m=0,00015m[/latex]

dane: q1 = q2 = q = 10^-6 C F = 4 x 10^5 N k = 9 x 10^9 [Nxm2/C^2] szukane: r = ?   F = k x q1q2/r^2      F = k x q^2/r2   I*r^2 F x r^2 = k x q2   /:F r^2 = k x q2/F = 9 x 10^9 x(10^-6)^2/(4 x 105) = 2,25/10^8  r = V(2,25/10^8) m r = 1,5 x 10^-4 m  = 0,00015 m ============================   [r] = V([k] x [q^2]/[F]) [r] = V([N x m^2/C^2]x[C^2]/[N]) [r] = m