Oblicz. (0,45-6 DWIE  TRZECIE-0,17:0,034)*(-2)2 Uprośc równanie (2y-3)2-(3y-2)(3y+2)= (5y+1)(1-5y)-(1+5y)2=   Rozwiąż równanie (3-x)2-x+jedna trzecia)2=dwie dziewiate rozwiąz nierówności 4(x-3)2-(2x-5)2=>_2

[latex](2y-3)^2-(3y-2)(3y+2)=4y^2-12y+9-9y^2+4 = -5y^2-12y+13[/latex]   [latex](5y+1)(1-5y)-(1+5y)^2 = 1-25y^2-1-10y-25y^2 = -50y^2-10y=10y(5y-1)[/latex]     [latex](3-x)^2-(x+frac{1}{3})^2=frac{2}{9}[/latex] [latex]9-6x-x^2-x^2-frac{2}{3}x-frac{1}{9}=frac{2}{9}[/latex] [latex]-2x^2-frac{20}{3}x+frac{26}{3}=0[/latex] [latex]-6x^2-20x+26=0[/latex] [latex]Delta=400+624 = 1024[/latex] [sqrt{Delta}=32[/latex] [latex]x_{1}=frac{20-32}{-12}=1[/latex] [latex]x_{2}=frac{20+32}{-12} = -frac{52}{12} =-4frac{1}{3}[/latex]     [latex]4(x-3)^2-(2x-5)^2 ge 2[/latex] [latex]4x^2-24x+36 - 4x^2+20x-25 ge 2[/latex] [latex]-4x ge -9[/latex] [latex]x le frac{9}{4}[/latex]   [latex]x in (-infty, frac{9}{4}>[/latex]