Bardzo proszę o pomoc Zad 8 Rozwiąż równanie [latex]( frac{5}{2})^ frac{4}{x}( frac{2}{5})^x( frac{2}{5})^{-1}=( frac{2}{5})^2 [/latex]

[latex]D:x eq0\\(frac{2}{5})^{-frac{4}{x}}cdot(frac{2}{5})^{x-1}=(frac{2}{5})^2\\(frac{2}{5})^{-frac{4}{x}+x-1}=(frac{2}{5})^2\\-frac{4}{x}+x-1=2\\-frac{4}{x}=-x+1+2\\-frac{4}{x}=3-x\\x(3-x)=-4[/latex] [latex]-x^2+3x+4=0\\Delta=3^2-4cdot(-1)cdot4=9+16=25; sqrtDelta=sqrt{25}=5\\x_1=frac{-3-5}{2cdot(-1)}=4in D vee x_2=frac{-3+5}{2cdot(-1)}=-1in D\\\©DRK[/latex]