wykonaj mnożenia : -4(3y-4x)= 4(a/2+b/2)= 2(a²+3b-4x-12)= -1/3(6x³-12x²-3x)= 1/4(1,2xy²-2y³-0,4y²)= 3(4xy²-3x²y-x³y-3yx)=

[latex]-4(3y-4x)= -12y+16x \ \4(frac{a}{2}+frac{b}{2})=2a+2b\ \2(a^2+3b-4x-12)=2a^2+6b-8x-24\ \ -frac{1}{3}(6x^3-12x^2-3x)=-2x^3+4x^2+3x[/latex] [latex]frac{1}{4}(1,2xy^2-2y^3-0,4y^2)=0,3xy^2-frac{1}{2}y^3-0,1y^2\ \3(4xy^2-3x^2y-x^3y-3yx)=12xy^2-9x^2y-3x^3y-9yx[/latex]