wyrazenia wymierne prosze o rozwiazania, zadania w załączniku 

[latex]Zad,1\a)\ frac{3x^2+7}{(x-7)(x-2)(x+3)} \(x-7)(x-2)(x+3) e0\x-7=0\x=7\lub\x-2=0\x=2\lub\x+3=0\x=-3\D:R-(-3;2;7)\b\ frac{4y^3-11y^2}{3y^2-18y+27}\3y^2-18y+27 e0\3y^2-18y+27=0|/3\y^2-6y+9=0\Delta(-6)^2-4*9=36-36=0\ x_{1,2}= frac{6}{2}=3\D: R-(3)\ [/latex] [latex]Zad,2\a)\ frac{x-1}{3x^2}* frac{5x^3}{x^2-1}\ 3x^2 e0\x e0\x^2-1 e0\x^2 e1\x e1\x e-1\xin R -(-1, 0, 1 )\ frac{x-1}{3x^2}* frac{5x^3}{x^2-1}=frac{x-1}{3x^2}* frac{x^2*5x}{(x-1)(x+1)}= frac{5x}{3(x+1)}\ c)\ frac{2x^2-18}{x^2-6x+9}* frac{x^2+2x}{3x+6}=frac{2(x-3)(x+3)}{(x-3)^2}* frac{x(x+2)}{3(x+2)}= frac{2x(x+3)}{3(x-3)(x+2)}=\= frac{2x^2+6x}{3(x^2+2x-3x-6)}= frac{2x^2+6x}{3(x^2-x-6)}\x-3 e0\x e3\x+2 e0\x e-2\xin R-(-2, 3 )\[/latex] [latex]Zad,3\a)\ frac{4}{x+3}- frac{2x}{x-1}= frac{4(x-1)-2x(x+3)}{(x+3)(x-1)}= frac{4x-4-2x^2-6x}{x^2-x+3x-3}= \ =frac{-2x^2-2x-4}{x^2+2x-3}\x+3 e0\x e-3\x-1 e0\x e1\xin R-(-3; 1 )\ c)\ frac{3}{2x-5}-frac{4}{4x^2-20x+25}=frac{3(2x-5)-4}{(2x-5)^2}=frac{6x-15-4}{(2x-5)^2}=frac{6x-19}{(2x-5)^2}\2x-5 e0\2x e5\x e2,5xin R-(2,5)\[/latex] [latex]Zad4\a)\ frac{2x-5}{x-1}= frac{2x+3}{x+2}\x-1 e0\x e1\x+2 e0\x e-2\(2x-5)(x+2)= (2x+3)(x-1)\ 2x^2+4x-5x-10=2x^2-2x+3x-3\-x-x=-3+10\-2x=7\x=-3,5\b)\ frac{5}{x}= frac{-x}{2x+2}\x e0\2x+2 e0\2x e-2\x e-1\5(2x+2)=-x^2\10x+10=-x^2\x^2+10x+10=0\Delta=10^2-4*10=100-40=60\sqrtDelta=sqrt{60]=2sqrt{15}\ [/latex] [latex]x_1= frac{-10-2sqrt{15}}{2}=-5-sqrt{15}\ x_2= frac{-10+2sqrt{15}}{2}=-5+sqrt{15}\[/latex]