Rozwiąż równanie. a) [latex]12x+ sqrt{3} x^2=0[/latex] b) [latex]( sqrt{2} -2)x^2= sqrt{2} [/latex] ODP. a)x∈ {[latex]{-4 sqrt{3} ,0}[/latex]} b) brak rozwiązania

[latex]a) \12x+ sqrt{3} x^2=0 \x( sqrt{3} x+12)=0 \x=0 quad vee quad sqrt{3} x+12=0 \x=0 quad vee quad sqrt{3} x=-12 \x=0 quad vee quad x=- frac{12}{ sqrt{3} } \x=0 quad vee quad x=-4 sqrt{3} \\oxed{x in {-4 sqrt{3} ,0}}[/latex] ========================= [latex]b)( sqrt{2}-2)x^2= sqrt{2} quad /: (sqrt{2}-2) \x^2= frac{ sqrt{2} }{ sqrt{2}-2 } \x^2= frac{2+2 sqrt{2} }{2-4} \x^2=underbrace{-1- sqrt{2}}_{<0} \\oxed{x in varnothing} [/latex]