Witam, jedno zadanie w załączniku. Usun niewymierność z mianownika. DAM NAJ

[latex] dfrac{3sqrt{10}}{2sqrt{2}} =dfrac{3sqrt{10} cdot sqrt{2}}{2sqrt{2} cdot sqrt{2}}=dfrac{3sqrt{20}}{4}=dfrac{3 cdot 2sqrt{5}}{4}=dfrac{3sqrt{5}}{2}[/latex] [latex] dfrac{7}{sqrt{2}-3} =dfrac{7(sqrt{2}+3)}{(sqrt{2}-3)(sqrt{2}+3)}=dfrac{7(sqrt{2}+3)}{2-9}=dfrac{7(sqrt{2}+3)}{-7}=-sqrt{2}-3[/latex] [latex] dfrac{4sqrt{5}}{9-sqrt{5}} =dfrac{4sqrt{5}(9+sqrt{5})}{(9-sqrt{5})(9+sqrt{5})}=dfrac{36sqrt{5}+20}{81-5}=dfrac{36sqrt{5}+20}{76}=dfrac{9sqrt{5}+5}{19}[/latex] [latex]dfrac{4}{sqrt{5}}=dfrac{4sqrt{5}}{sqrt{5} cdot sqrt{5}}=dfrac{4sqrt{5}}{5}[/latex] [latex]dfrac{3sqrt{2}}{sqrt{6}}=dfrac{3sqrt{2} cdot sqrt{6}}{sqrt{6} cdot sqrt{6}}=dfrac{3sqrt{12}}{6}=dfrac{3 cdot 2sqrt{3}}{6}=sqrt{3}[/latex]