2 kg cyny ogrzano dostarczając 4 KJ ciepła. O ile ogrzano cynę? Daje NAJ

m = 2 kg Q = 4 kJ = 4000 J cw = 220 J/kg * C Δt = ? [latex]Q = m * c_w * Delta t /: m* c_w[/latex] [latex]Delta t = frac{Q}{m*c_w } [/latex] [latex]Delta t = frac{4000 J }{2 kg * 220 frac{J}{kg * C} } = 9,1 C[/latex]